F(x)=2^2-3x+7

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Solution for F(x)=2^2-3x+7 equation: 



(F)=2^2-3F+7

We move all terms to the left:

(F)-(2^2-3F+7)=0

We get rid of parentheses

F+3F-7-2^2=0

We add all the numbers together, and all the variables

4F-11=0

We move all terms containing F to the left, all other terms to the right

4F=11

F=11/4

F=2+3/4

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